concatenate-non-zero-digits-and-multiply-by-sum-i

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Algorithms

You are given an integer <code>n</code>.

Form a new integer <code>x</code> by concatenating all the non-zero digits of <code>n</code> in their original order. If there are no non-zero digits, <code>x = 0</code>.

Let <code>sum</code> be the sum of digits in <code>x</code>.

Return an integer representing the value of <code>x * sum</code>.

&nbsp;
Example 1:

<div class="example-block">
Input: n = 10203004

Output: 12340

Explanation:

<ul>
	<li>The non-zero digits are 1, 2, 3, and 4. Thus, <code>x = 1234</code>.</li>
	<li>The sum of digits is <code>sum = 1 + 2 + 3 + 4 = 10</code>.</li>
	<li>Therefore, the answer is <code>x * sum = 1234 * 10 = 12340</code>.</li>
</ul>
</div>

Example 2:

<div class="example-block">
Input: n = 1000

Output: 1

Explanation:

<ul>
	<li>The non-zero digit is 1, so <code>x = 1</code> and <code>sum = 1</code>.</li>
	<li>Therefore, the answer is <code>x * sum = 1 * 1 = 1</code>.</li>
</ul>
</div>

&nbsp;
Constraints:

<ul>
	<li><code>0 &lt;= n &lt;= 109</code></li>
</ul>

Weekly Contest 477

weekly-contest-477

sumAndMultiply

Mid Level

Concatenate Non-Zero Digits and Multiply by Sum I

Math

Accepted

Wrong Answer

Memory Limit Exceeded

Output Limit Exceeded

Time Limit Exceeded

Runtime Error

Internal Error

Compile Error

Timeout

Restrictions Failed

cangjie

react

vanillajs

You are given an integer n.

Form a new integer x by concatenating all the non-zero digits of n in their original order. If there are no non-zero digits, x = 0.

Let sum be the sum of digits in x.

Return an integer representing the value of x * sum.

 

Example 1:

Input: n = 10203004

Output: 12340

Explanation:

 * The non-zero digits are 1, 2, 3, and 4. Thus, x = 1234.
 * The sum of digits is sum = 1 + 2 + 3 + 4 = 10.
 * Therefore, the answer is x * sum = 1234 * 10 = 12340.

Example 2:

Input: n = 1000

Output: 1

Explanation:

 * The non-zero digit is 1, so x = 1 and sum = 1.
 * Therefore, the answer is x * sum = 1 * 1 = 1.

 

Constraints:

 * 0 <= n <= 109